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1 - 1 of 1 for ChebyshevT
In the specific case a = 4 , however, it turns out that by allowing more sophisticated mathematical functions one can get a complete formula: the result after any number of steps t can be written in any of the forms Sin[2 t ArcSin[ √ x ]] 2 (1 - Cos[2 t ArcCos[1 - 2 x]])/2 (1 - ChebyshevT[2 t , 1 - 2x])/2 where these follow from functional relations such as Sin[2x] 2  4 Sin[x] 2 (1 - Sin[x] 2 ) ChebyshevT[m n, x]  ChebyshevT[m, ChebyshevT[n, x]] For a = 2 it also turns out that there is a complete formula: (1 - (1 - 2 x) 2 t )/2 And the same is true for a = -2 : 1/2 - Cos[(1/3) ( π - (-2) t ( π - 3 ArcCos[1/2 - x]))] In all these examples t enters essentially only in a t . And if one assumes that this is a general feature then one can formally derive for any a the result 1/2 (1 - g[a t InverseFunction[g] [1 - 2x]]) where g is a function that satisfies the functional equation g[a x]  1 + (a/2) (g[x] 2 - 1) When a = 4 , g[x] is Cosh[Sqrt[2 x]] .
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